write balanced molecular equation for the reaction between nitric acid and calcium hydroxide.

Nitric corrosive has the substance recipe HNO3, and Calcium Hydroxide has the compound equation Ca(OH)2. At the point when a corrosive and a base respond with one another, the items that are framed is a salt (an ionic compound that is shaped from a response between a corrosive and a base) and water. 

Thus, corrosive + base - - > salt + water 

Presently, to adjust the condition, we need to ensure there are similar number of molecules (or particles) on the two sides of the situation. Additionally, we should list the condition of each compound in the situation.

HNO3 (aq) + Ca(OH)2 (aq) ---> Ca(NO3)2 (aq) + H2O (l)

Number of atoms before the reaction:
H = 3
N = 1
O = 5
Ca = 1
Number of atoms after the reaction:
H = 2
N = 2
O = 7
Ca = 1

There are not the same number of atoms on both sides of the equation, so we must balance it. Remember to place the balancing numbers in front of the chemical formulas.

2HNO3 (aq) + Ca(OH)2 (aq) ---> Ca(NO3)2 (aq) + 2H2O (l)

Number of atoms before the reaction:
H = 4
N = 2
O = 8
Ca = 1
Number of atoms after the reaction:

H = 4
N = 2
O = 8
Ca = 1

There are now the same number of atoms on both sides of the equation, so that is the balanced chemical equation between nitric acid and calcium hydroxide.